If it's not what You are looking for type in the equation solver your own equation and let us solve it.
8x^2-12x-3=0
a = 8; b = -12; c = -3;
Δ = b2-4ac
Δ = -122-4·8·(-3)
Δ = 240
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{240}=\sqrt{16*15}=\sqrt{16}*\sqrt{15}=4\sqrt{15}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-4\sqrt{15}}{2*8}=\frac{12-4\sqrt{15}}{16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+4\sqrt{15}}{2*8}=\frac{12+4\sqrt{15}}{16} $
| −3x−34(89x+43)=6(13−19x) | | 14=(3u-8)/2+(9u-3)/8 | | -1/6(y+3)=1/2(y+1/9) | | 4e+16=32 | | 77x^2-550x-1000=641 | | x/8-9=-8 | | 14=(3u-8/2)+(9u-3/8) | | 5x+9=3x+10 | | 12y+60+3y=180 | | 70=-16.4t^2+80t | | 6x-(2+3)=0 | | 4x^2+21=18 | | 6x+12x+60=180 | | 8+x/2=31 | | x-8=2x-12 | | 3/4n-18=1/4n=4 | | a/6+4=9 | | 4m+2=3m+16 | | -5+25x=95 | | -3=4(-x+5) | | -27=y/5-2 | | x/3-4.1=13.7 | | 40x-14+20x=106 | | 6x-13=-25 | | x/3+4.1=13.7 | | 3x-5=2x+3=7x-17=5x-12 | | X/2-x/6+2=x+2 | | 40a-14+20a=106 | | -4x-5=-5x+3 | | 3x-4.1=13.7 | | 7,2-8x=9,2·2x | | 5x-20=12x+8 |